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Ah, I'd like

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#81 makeskidskill

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Posted 09 May 2007 - 6:01 PM

It can be.




#82 makeskidskill

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Posted 09 May 2007 - 6:02 PM

No it can't. An argument is a connected series of statements intended to establish a proposition.


(chemicalreaction, if you're so deprived as to not know your Monty Python, then I'm sorry for you, but don't interrupt the arguement. There is a point, I promise. Love, Stash)




#83 Csar   User is offline

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Posted 09 May 2007 - 6:03 PM

No it isn't



E(argasm) = m(usic) x c(hemicals)²

#84 makeskidskill

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Posted 09 May 2007 - 6:03 PM

Yes it is! It's not just contradiction.




#85 chemicalreaction   User is offline

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Posted 09 May 2007 - 6:04 PM

bwahhhh..its entertaining.

Continue as before.




#86 Csar   User is offline

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Posted 09 May 2007 - 6:05 PM

Look, if I argue with you, I must take up a contrary position



E(argasm) = m(usic) x c(hemicals)²

#87 makeskidskill

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Posted 09 May 2007 - 6:07 PM

Yes, but that's not just saying 'No it isn't.'




#88 Csar   User is offline

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Posted 09 May 2007 - 6:09 PM

Yes it is!



E(argasm) = m(usic) x c(hemicals)²

#89 makeskidskill

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Posted 09 May 2007 - 6:10 PM

No it isn't!




#90 makeskidskill

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Posted 09 May 2007 - 6:12 PM

Yes, it is!




#91 makeskidskill

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Posted 09 May 2007 - 6:13 PM

Argument is an intellectual process. Contradiction is just the automatic gainsaying of any statement the other person makes.




#92 makeskidskill

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Posted 09 May 2007 - 6:14 PM

No it isn't.




#93 makeskidskill

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Posted 09 May 2007 - 6:15 PM

It is.




#94 makeskidskill

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Posted 09 May 2007 - 6:16 PM

Not at all.




#95 Csar   User is offline

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Posted 09 May 2007 - 6:16 PM

Not at all



E(argasm) = m(usic) x c(hemicals)²

#96 makeskidskill

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Posted 09 May 2007 - 6:17 PM

Now look....




#97 Csar   User is offline

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Posted 09 May 2007 - 6:17 PM

(Rings bell) Good Morning



E(argasm) = m(usic) x c(hemicals)²

#98 makeskidskill

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Posted 09 May 2007 - 6:19 PM

What?!




#99 Csar   User is offline

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Posted 09 May 2007 - 6:20 PM

That's it. Good morning



E(argasm) = m(usic) x c(hemicals)²

#100 makeskidskill

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Posted 09 May 2007 - 6:21 PM

I was just getting interested.




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